Python using RStudio IDE
Today is 7/26
This is test post to check if Python code works
library(reticulate)
## Warning: package 'reticulate' was built under R version 3.4.4
import numpy as np
x = [1, 2, 3]
print(x)
## [1, 2, 3]
y = np.mean(x)
\(\bar{x}\) is the average, which is defined as \[ \bar{x} = \frac{\sum x}{n} \]
So what is the aveage of y
? It is 2
.
x = c(1:5)
The value of x is R session is 1, 2, 3, 4, 5
.
More text is to be added.
R Markdown
This is an R Markdown document. Markdown is a simple formatting syntax for authoring HTML, PDF, and MS Word documents. For more details on using R Markdown see http://rmarkdown.rstudio.com.
You can embed an R code chunk like this:
summary(cars)
## speed dist
## Min. : 4.0 Min. : 2.00
## 1st Qu.:12.0 1st Qu.: 26.00
## Median :15.0 Median : 36.00
## Mean :15.4 Mean : 42.98
## 3rd Qu.:19.0 3rd Qu.: 56.00
## Max. :25.0 Max. :120.00
fit <- lm(dist ~ speed, data = cars)
fit
##
## Call:
## lm(formula = dist ~ speed, data = cars)
##
## Coefficients:
## (Intercept) speed
## -17.579 3.932
```
Testing LaTeX
This is an inline test for math content in markdown \(\bar{x}\). And this is a mathe block, defining the average– \[ \bar{x} = \frac{\sum x}{n} \]
And some more complicated formula
\[ y = x_1 \beta_1 + x_2 \beta_2 + \epsilon \] is the multiple linear regression model with two covariates \(x_1\) and \(x_2\).
When \\( a \ne 0 \\), there are two solutions to
$$ ax^2 + bx + c = 0 $$
and they are:
\\[ x = {-b \pm \sqrt{b^2-4ac} \over 2a} \\]